anoder one!!!

If points x,y are choseaban for randomly from the interval [0,2] and [0,1] respectively then probabilty that y=<x2 is k/3 then k is

11 Answers

106
Asish Mahapatra ·

hint : plot the inequality y ≤ x2

106
Asish Mahapatra ·

total area = 2
favourable area = 0∫1x2dx = 1/3

So, prob. = (1/2)*(1/3)

=> k = 1/2

so ur correct kunl

106
Asish Mahapatra ·

ricky : again ... it is y ≤ x2 so it will be ∫x2dx ??

1
seoni ·

think a bit more---ans is k=2

1
Ricky ·

Nopes , I have integrated over " y " , not " x " .

1
seoni ·

look for the 'favourable' and 'total' area carefully,,,

fav area= 1/3+ 1*1 [???]

total=2*1

1
Ricky ·

Can you draw a graph and explain please ?

1
seoni ·

i think this is self explanatory..

1
kunl ·

i was doubting this thing only~ths y wanted confirmation....whether we were to nclude this area or not!
thanx for confirmation!

1
Ricky ·

Hmm , I sketched the wrong area . Thanks Seoni.

1
kunl ·

seoni cn u verify answers to other questions asked by anshuiit today?

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