total area = 2
favourable area = 0∫1x2dx = 1/3
So, prob. = (1/2)*(1/3)
=> k = 1/2
so ur correct kunl
If points x,y are choseaban for randomly from the interval [0,2] and [0,1] respectively then probabilty that y=<x2 is k/3 then k is
total area = 2
favourable area = 0∫1x2dx = 1/3
So, prob. = (1/2)*(1/3)
=> k = 1/2
so ur correct kunl
look for the 'favourable' and 'total' area carefully,,,
fav area= 1/3+ 1*1 [???]
total=2*1
i was doubting this thing only~ths y wanted confirmation....whether we were to nclude this area or not!
thanx for confirmation!