a straight line through a (-5,-4) meets the lines x+3y+2=0,2x+y+4=0 and x-y-5=0 at b,c,d respectively..........
if (15/ab)^2+(10/ac)^2=(6/ad)^2
then the equationof the straight line??
1a straight line thrugh -5,-4
(y+4) = m (x+5) => y = mx+ 5m-4 -------[ i]
now, get the point of intersections b,c,d of this line wid the other lines in trems of 'm'.
u are given another eqn.
put b,c,d there... so u will get the value of 'm'.
put it in eqn. [ i]
bus [1]
1koi agar topic nahi dekhega toh sochega main pagal ho gayi...
khud question post karke ..soln post kar rahi hu [3] [3] [3]
1thats crazy!!!
haha.........
any how thanks for trying and solving the problem.......
but I think the problem is tooo lengthy!!!
k thanks once again
