11nishant sir... ye to mere se nahi ho raha....
ap kar dijiye na....
pls...
Let the sides of a triangle ABC are all integers with A as the origin. If (2,-1) and (3,6) are points on the line AB and AC respectively(lines AB andAC may be extended to contain these points),and lengths of any two sides are primes that differ by 50. find the smallest possible value of the third side.
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8 Answers
62B will be (2k, -k) while c will be (m, 2m)
They will form a right angled triangle because of the slopes...
Now we have that two sides are primes and differ by 50. (And are prime numbers)
So the question is reduced to another question which is no longer from coordinate geometry.. You give it a shot from here? I have discussed that form here.. but dont know if you have seen that earlier!
1162see there is a result for phythagorean triplets
they are
2n+1, 2n^2+2n and 2n^2+2n+1
Now you can finish it off?
The difference of the largest adn smallest is when 2n^2=50 or n=5
Thus, the sides are 11, 60 and 61
1let PQ $ RS be tangents at extremities of diameter of a circle (PR) of radius r. if PQ & RS intersect at a point X on the circumference of the circle , then 2r =
a) √PQ . RS b) ( PQ + RS ) / 2
c) 2 PQ . RS /( PQ + RS) d ) { √( PQ2 + RS2) }/ 2
1don't u thnk tangents at the extremeties of diameter are parallel to each other so how wuld they ever intersect ?