it is 6 ,try putting ω in the eqn as it is clear that A is some kth root of unity
suppose A is a complex no. & n belong to N,such that An =(A+1)n=1.then least value of n is,
1.3
2.6
3.9
4.12
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6 Answers
Vivek
·2009-04-04 06:19:19
Lokesh Verma
·2009-04-04 06:37:47
An = (A+1)n = 1
take mod on both sides
then |A|=|A+1|
thus A lies on bisector of 0 and -1 thus Re(A)=-1/2
|A| = 1 hence Im(A) = ±√3/2
now see that -1/2±√3/2i = ei pi/3
now does it make the answer obvious?
Vivek
·2009-04-04 11:17:21
using ω,
ωn=1 implies n =3,6,9 .......
(ω+1)n=(-ω2)n = 1 implies n = 6,12,18 .....
so least value is 6