find the co-ordinates of the foot of the perpendicular drawn from the point (2,-5) on the straight line x=y+1 ?
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1 Answers
19slope of given line=1
thus slope of its perpendicular = -1...and this perp passes though (2,-5)
...eqn of perp is y+5=-1(x-2)
....solving it with x=y+1 ...we get (x,y) =(-1,-2)
