xsecθ+ycosecθ=a => x/ (acosθ) + y/ (asinθ) =1
....slope = -cot θ
,,,eqn of st line through (acos3θ,asin3θ) and slope -cot θ is
y - asin3θ= -cot θ(x - acos3θ)
=> xcosθ-ysinθ=acos2θ
...hence proved !
show that the equation of the straight line passing through (acos3θ,asin3θ) and perpendicular to the straight line xsecθ+ycosecθ=a is xcosθ-ysinθ=acos2θ ?
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1 Answers
Debotosh..
·2009-11-28 18:33:19