CO-ORDINATE SYSTEMS AND COORDINATES

my answer is coming 5....pls verify and then i`l post my solution....

draw a perpendicular first from the point(A) to the line....you can find out its length from the equation of the line....

length of the perpendicular =magnitude of[ ax + by +c/√a² + b²]

the length is coming as 3 units....{actually u don`t need to use the above formula}

now draw the diagram...give the name of the perpendicular as AP....draw a right-angled triangle with AP as the height and PB as the base (where B is any arbitrary variable point on the line)....
so in triangle APB....AB<=4....so PB<=√7 by pythagorus theorem,which is approximately equal to 2.6 units
u can find out the co-ordinates of P = (6,4)
since PB is a line parallel to the y-axis and PB = 2.6 units....we can simply add or subtract the y co-ordinates of P to all the integers less than 2.6(that is 1 and 2) to get the y-co-ordinates of B
the co-ordinates of B = (6,5);(6,6);(6,2);(6,3) and (6,4) [since B can also take the co-ordinates of P as AP less than 4 units........i hope u`ve understood