1
decoder
·2009-09-13 04:38:22
(2) let (h,k) be the centre
since the coordinate axis is touching the ellipse, origin is the point from which the two tangents are drawn.
now write general eq. (x-h)2/a2 +(y-k)2/b2=1
and then use T=0
sow homogenise T=0 with ellipse and put (coefficient of x2)+(coefficient of y2)=0
u will get the locus of centre
1
decoder
·2009-09-13 04:50:35
i have got also one elegant method for (2)
hint: since the tangents are perpendicular therefore the locus of point of their intersection is the director circle of ellipse .
3
iitimcomin
·2009-09-16 02:57:33
but dude .... (x-h)2/a2 +(y-k)2/b2=1 is the equation og an ellipse whose center is at h.k but whose major axis is parallel to the co-ordinate axis ...... but this is not the case here na
3
iitimcomin
·2009-09-20 09:26:30
some 1 help!!!!!!!!!!!!!!
19
Debotosh..
·2009-09-20 09:30:40
locus of the centre is :x2 + y2 =a2 +b2
19
Debotosh..
·2009-09-20 09:37:12
we get only an arc of a circle while tracing the locus of the centre
3
iitimcomin
·2009-09-22 09:11:40
organic that is given in the question only that it forms an ark!!. ......