Eqn of Angle Bisector

eqn of pq
y=0
and
eqn of qr
y-√3x=0
so equation of angle bisector
y/√(1)=±( (y-√3x)/√(3+1) ) )
ie
2y=±(y-√3x)

line QR makes angle 60° with the x-axis hence m=√3...so angle PQR is 180°-60°=120°
so the bisector will make 60° with both PQ and QR ....so for the bisector m=tan 120°= -√3
so the equation of the bisector is y=-√3x....
actually in the options the greator angle bisector's equation is not considered

@maths_psycho the angle is obtuse yaar....how can "greator angle bisector's equation" not be considered ?

PQR forms two angles 120° on the positive side of y-axis...and d rest 240° on the oder side...but it a norm dat whenever we say about angle bisector,we mean d bisector of the angle which is least of the 2...