???
A triangle the lengths of whose sides are a,b&c is placed such that the mid points of its sides
are on the coordinate axes , if the equation of the plane of the triangle be
x/α + y/β + z/γ=1 then
(A) α = 1/2 √(a2+b2+c2)/2
(B) (a2+b2+c2)/ (α2+β2+γ2) = 8
(C) c =2√α2+β2
(D) (b2-a2)/(α2-β2)= 4
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