1
Arshad ~Died~
·2009-10-03 08:53:49
let us not let this thread die away without being solved..........
evryone pls tryyyyyyyyyyyyyyyy...............
nishant sir..........pls solve
4
UTTARA
·2009-10-01 10:28:57
Sorry It's 2R sq instead of 4R sq in the pic !!!!!!!!!!
1
RAY
·2009-10-01 10:37:48
u cannot move inside uttara...warna nishant bro ye question sayad hi post karte..lol
EVERYONE KNWS THE SHORTEST DISTANCE BETWEEN TWO POINTS IS A ST LINE..so dat wouldnt be apossible answer to such a long thread
ANOTHER QUESTION PERTAINING TO THE TOPIC
shortest path around cylinder
An ant starts at a point on the bottom edge of a right circular cylinder of radius and height . If the ant makes complete circuits around the cylinder and finishes at a point at the top edge directly above its starting point, find, with justification, the length of its shortest possible path.
24
eureka123
·2009-10-01 10:56:00
basically what mistake uttara is commitin is that she is moving the ant on straight line.....it wont move on stragiht line inside the cylinder..beczo of curvature..
1
$ourav @@@ -- WILL Never give
·2009-10-01 11:00:39
R√2 is obtained when we take the path across a chord which makes 90° at d centre of d circle...
1
$ourav @@@ -- WILL Never give
·2009-10-01 11:08:18
if i take a case of values,my answer is smaller dan uttara...plz check
4
UTTARA
·2009-10-01 19:22:36
@eureka123 : Do v need to consider the insect ???? In Nishant sir's Qs it's just mentioned to find the shortest dist b/w two opposite vertices on a cylinder !!!
@maths _psy : How R √2 I don't get u ? Which chord n circle r u considering?
24
eureka123
·2009-10-01 20:18:21
well I read teh topic of thread and replied.....If it is not insect then not much to wory..but if it is insect then we certainly cant go that way[6]
1
aposlil
·2009-10-02 01:00:41
there is more to this question than it meets the eye
1
Arshad ~Died~
·2009-10-02 07:38:53
so nishant sir whats the answer..........????
1
Arshad ~Died~
·2009-10-02 07:40:31
everyone see this for hint
http://www.mathhelpforum.com/math-help/geometry/45778-shortest-path-around-cylinder.html
23
qwerty
·2009-10-02 07:59:20
wat about the cube one ka answer??
23
qwerty
·2009-10-02 08:18:43
i hav posted the ans already scroll up...i jus wana confirm..and confirmed!!
1
RAY
·2009-10-01 10:05:23
can u move from inside the cylinder uttara?
4
UTTARA
·2009-10-04 11:59:50
@xyz : Y do v need to open up the cylinder when v have no conditions like not travelling
inside I dont get ur point!!
62
Lokesh Verma
·2009-10-04 22:45:54
Let me give a hint..
what uttara and maths_phys have done in post 28 and 19 respecitvely are correct.. (Both take a straight line)
But there is one small missing thing....
The final answer will depend on the function/. relation between r and L
Think about it?
4
UTTARA
·2009-10-05 06:40:12
@Nishant Sir can we say the shortest distance is achieved at L = 4R ???????????/
i.e. shortest dist = √20R2
62
Lokesh Verma
·2009-10-05 06:49:07
no uttara.. the way I think this will work.. is that
We have to compare 2R+L and √(piR)2+L2
which is 4R2+4RL+L2 > (piR)2+L2
which is 4R2+4RL > (piR)2
0 > (piR-4L)R
0 > (piR-4L) (since R>0 always)
so if R<4L/pi
then you will have the first path
otherwise the 2nd path... [1]
4
UTTARA
·2009-10-05 09:56:16
But Nishant Sir y do v need to compare 2R + L & √(piR)2 + L2
I've considered √(2R)2 + L2 < √(piR)2 + L2
62
Lokesh Verma
·2009-10-08 07:34:28
Qwerty dont worry about pinked posts as much.. it is my request to all users here.. I kind of feel bad when i see that the motivation to interact here is the number of posts or number of pinked posts etc..
We are all here not to give or take more pinked posts but to learn new stuff.. Even I keep learning everyday here.. Believe it or not, I think that I am one person who has learnt most here!
1
Praveen kumar singh
·2009-10-09 02:13:43
i am unable to understand how we are getting to equation of conjugate hyperbola from the standard eqn of the hyperbola .please help.
1
Praveen kumar singh
·2009-10-09 02:35:47
i am unable to understand how we are getting to equation of conjugate hyperbola from the standard eqn of the hyperbola .please help.
1
Arshad ~Died~
·2009-10-18 03:37:58
635 views-51 replies
and the 2nd question is still unsolved....
1
Arshad ~Died~
·2009-11-04 03:49:09
nishant sir pls post the solution to ur question.....
49
Subhomoy Bakshi
·2010-02-03 05:32:47
i get the soln...:P
cut open the cylinder
reqd distance is..\sqrt{(2\pi r)^2+L^2}
thats the answer....for sure...[1][1][1]
1
Philip Calvert
·2010-02-03 06:31:00
@ ATGS : thats precisely what everyone else was discusing ,,,yaar :D
there will be cases...
1
injun joe
·2009-09-30 08:36:15
It seems so.
Or am not thinking deeply enough.Latter seems more likely
1
Arshad ~Died~
·2009-09-30 04:32:43
i didnt intend u to answer sir,,,,,,,,,pls let some junior answer this one
62
Lokesh Verma
·2009-09-30 04:33:42
A slightly different and seemingly difficult... . but it will be a better question....
what will be the shortest point on the opposite "vertices" of a cylinder
1
injun joe
·2009-09-30 04:46:40
Do I come in juniors?? I've seen this one before (though not nishant sir's)