Co-ordinate Geometry - insect quest

1

Arshad ~Died~ ·2009-09-30 05:06:48

injun read the p.s.

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Lokesh Verma ·2009-09-30 05:10:28

The question I gave just not is one that even I had not seen before :D :D

But i think there is a good solution too ;)

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1

injun joe ·2009-09-30 06:58:37

Sir's question

Shortest distance is 4R+L

R- Radius
L- Length of the cylinder

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62

Lokesh Verma ·2009-09-30 07:37:13

2R+L could have been an answer..? ??

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62

Lokesh Verma ·2009-09-30 07:37:29

but I think there is a better answer.. :)

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1

injun joe ·2009-09-30 08:18:51

2R+L kaise??

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62

Lokesh Verma ·2009-09-30 08:19:48

first move towards the top.. Length L

then cross the diameter.. 2R

hence the answer :)

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1

injun joe ·2009-09-30 08:29:13

ughhh!
Yet another slip!!!
2nd of the day
Sorry sir.....

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62

Lokesh Verma ·2009-09-30 08:33:57

but this is not the final answer.. is it?

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62

Lokesh Verma ·2009-09-30 04:25:07

"Removed my answer"

funnily this question also i discussed in the class IX that i am taking :D

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1

Philip Calvert ·2009-09-30 11:26:24

Unless I am sleeping.. this one is a sitting sitter

\sqrt{(\pi R)^{2}+L^{2}}

incomplete !

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1

$ourav @@@ -- WILL Never give ·2009-09-30 12:13:51

i did arshad's ques in class 9....but i got trapped in it at dat time

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1

$ourav @@@ -- WILL Never give ·2009-09-30 12:33:27

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$ourav @@@ -- WILL Never give ·2009-09-30 12:38:36

in my above diagram....d shortest distance will be by moving from A to B ,den to C....where B and Cmake 90Â° at the centre of the bottom circle...so the minimum distance cumes out as

√[ (Ï€R/2)² + L² ] + R√2

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$ourav @@@ -- WILL Never give ·2009-09-30 12:39:36

isnt it nishant sir???

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23

qwerty ·2009-09-30 22:39:00

for such questions .....convert d 3D fig into a 2D fig ....then its a pythagoras type question [ thats how i solved the cube wala]
btw is the answer of the cube one = x(âˆš5)???
[ shortest length = âˆš(2x)² + x² ]

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62

Lokesh Verma ·2009-09-30 22:59:27

There is much moer to this question...

i mean the cyllinder one...

[1]

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$ourav @@@ -- WILL Never give ·2009-10-01 04:21:52

sir,i did it by pythagoras theorem in a 2-d figure....sir.,plz give d solution....

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62

Lokesh Verma ·2009-10-01 06:18:57

where did you get r√2 ??

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4

UTTARA ·2009-10-01 07:33:28

@Nishant Sir : Can this be a solution?

First travel R to reach the centre of top circular edge and then travel √ R² + l² to reach the required point on the opposite side of the bottom circular edge

Shortest since R + l > √R² + L²

Therefore total dist = R + √R² + L²

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62

Lokesh Verma ·2009-10-01 08:16:02

There is a small mistake...

will it be r or 2r?

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