1The circle concentric to the circle passing through
(0,2) (-6,-2) (-3,-6)
and having radius bigger by 3 units.
Find the equation of the circle of minimum radius which contains the 3 circles.
x2 + y2 - 4y - 5 = 0,
x2 + y2 + 12x + 4y + 31 = 0,
x2 + y2 + 6x + 12y + 36 = 0,
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14 Answers
1
1hey philp......why will that circle be concentric with cicle passing through centers of respective circels.....give the proof.....
1@ BugsBunny and debo.. the sides of the triangle will be √52 , 5 , √73 ??
19yes sorry for the stupid thing ! confused with (+) and (-) ! but your process is all right !!!
1wait.......but then also why will that circle be concentric with cicle passing through centers of respective circels.....din get
19simplest thing is that the circle must touch all of them externally ,,,,that leads us to the conclusion from philip !
1its answer is (x +31/18)2 + (y+23/12)2 = (3+5√949/36)2.
Did anyone reach at the result?
19yes we can get that with some patience , when we observe that this required circle is concentric with the circle passing through the centres of the three circles. the later can be found out with the help of the points through which it passes(i mean the centres of the 3 given circles) and then the result is obvious !
1do it.......coz the ONLY TRICK to crack mathematics is to solve it.......not just create a mind-map for solving it/preparing the algorithm for solving it!
Ur calculations should also be very fast........coz u dont get hours for each ques......u get just-1-3 min in any competitive exam for Engg!!!