general eqn of tangent for 1st - > y = mx+a/m
general eqn of tangent for 2nd - > x = ty+a/t
now for common tangent, the above two eqns. are identical .
compare and find m and t.
Equation of the common tangent to the parabolas :
y^2 = 4ax; x^2 = 4ay
general eqn of tangent for 1st - > y = mx+a/m
general eqn of tangent for 2nd - > x = ty+a/t
now for common tangent, the above two eqns. are identical .
compare and find m and t.
I am a bit confused about this problem. Could anyone give the complete solution. Thnxs in advance.