The following eqn represents two straight lines.
6y2-xy-x2+30y+36=0
Find their point of intersection and the angle between them.
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3 Answers
Lokesh Verma
·2010-01-22 08:11:05
for finding the slope you simply have to find the slope of the lines
6y2-xy-x2 = 0
you get (3y+x)(2y-x)
so we get the above eqtn is of the form
(3y+x+a)(2y-x+b)
now compare coefficients....
Can you complete therest?
sumit_kumar
·2010-01-22 08:25:37
Plz say me how did u get
6y2-xy-x2=(3y+x)(2y-x)
....the rest i can solve
Lokesh Verma
·2010-01-22 22:49:33
factorize..
or solve for y in terms of x
the above expression is a quadratic in both x and y
so you can solve either for x or for y