parabola-1

wat is eq. of directrix , axis, length of latus rectum of 9x2 -24xy+16y2 -20x-16y-60=0 plz reply

24 Answers

24
eureka123 ·

yup its very much in sylllabus.................even if it is not mentioned in parabola section.............still rotation and translation of axes is there in syllabus........so dont get surprised on seeing a question like this........

33
Abhishek Priyam ·

finally..

1
rahul wadhwani ·

eureka u r correct & ans. too & thanx very much

9
Celestine preetham ·

ne way that post wont be of relevance now as rahul edited q

24
eureka123 ·

okkkkkkkk....but shift of origin is there,sky.......

So dont ignore it...........

9
Celestine preetham ·

yes sky noted ;)

1
skygirl ·

arey fiitjee ppl are experts gving out-of-syllabus questions...

even they din gv such a question .. [3]

62
Lokesh Verma ·

eureka... shifting fo coordinate is there but not the rotation...

Never has one such question come nor do i see such a possibilty

24
eureka123 ·

see in the begiining.......analytical geometry starts.........1st para last word """SHIFT OF ORIGIN"""............it applies to full coordinate geometry........

1
skygirl ·

whether its in syll..

it tells ... only in std form...

24
eureka123 ·

on what?????????

1
skygirl ·

i doubt [12]

1
rahul wadhwani ·

hey anyone trying yaar

3
msp ·

These parabola eqns are included in jee syllabus.

These forms can be seen in our school textbooks itself

24
eureka123 ·

but we need a pair of perpendicular lines
3x-4y & 4x+3y+12...............i hope u got my point...............

1
skygirl ·

but its not always like u will get a perfect square...

24
eureka123 ·

I think it should be -15y there..............Then it is solvable(becoz then only we get coordinate axes rotated by some angle)

giving the soln with -15y................

(3x-4y)2-5(4x+3y+12)=0
=> (3x-4y)2=5(4x+3y+12)

Divide both sides by 5
=> (3x-4y)2/5=5(4x+3y+12)/5
=> ((3x-4y)/√32+42)2 5=5[(4x+3y+12)/√32+42]

=>Y2=4AX

where Y=(3x-4y)/5 and X=(4x+3y+12)/5 and 4A=1

We know that directrix => X=-A
=> (4x+3y+12)/5 =-1/4
=> 4x+3y+53/4=0

I hope u can get focus now.......

1
skygirl ·

and yeah celestine...

if its a typo , then very fine :)

but if its not... then lemme correct...

h2<ab is for an ellipse...

1
skygirl ·

well... its not in jee syll...

but sankara has given the method...n i dun have a short cut ...

3
msp ·

rahul reduce the given eqn to Y2=4aX

Y=ax+by+c
X=lx+my+n

11
Subash ·

i think this is not in the jee syllabus

i know only to find the centre

partially differentiate separately wrt x and y

and solve the equations

sry thats wht i knew

1
rahul wadhwani ·

hey edited cele now see

1
rahul wadhwani ·

u r wrong it is 'coz it is not standard form axis is not ll to axes

11
Anirudh Narayanan ·

Parabola? Looks more like a pair of straight lines or something like that. [7]

Cos in parabola (i'm not sure of it) there won't be any xy term

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