12. now the axis is along x-axis so the eq is of the form Y2=4aX.but coordinates of vertex nd focus are (h,0)and (k,0) respectively. therefore the eq is, y2=4k(x-h).
1.The equation of the parabola whose vertex is origin, axis is along y-axis and which passes through the point (2,1) is
2.The vertex and focus of a parabola are at a distance are at a distance of h and k units on positive x-axis from origin then equation of parabola is
3.The eq. of parabola whose axis is parallel to x axis and passing through (-2,1) , (1,2) , (-1,3) is
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3 Answers
11. as the axis is along y-axis so it is symmetric about y-axis , and hence the eq is x2=4ay .Putting the above given values we have a=1 , therefore the eq is x2=4y
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