(x+a/4)2 =1/2 [y - (1-a2/8)]
and
(x-1/8)2 = -1/4[y - (a+1/16)]
then from the questn..
1 - a28 < a + 116.
and
a > 0.
evaluate a.
Set of all positive values of a for which distance of vertex of y=2x2+ax+1 from x-axis is less than distance of vertex of y=-4x2+x+a from x-axis,is
(x+a/4)2 =1/2 [y - (1-a2/8)]
and
(x-1/8)2 = -1/4[y - (a+1/16)]
then from the questn..
1 - a28 < a + 116.
and
a > 0.
evaluate a.