1y2=4a (x-λ1)
x2=4a (y-λ2) {I think your second equation wrong!)
y2/4a + λ1 =x
substitute x in the 2nd equation
(y2/4a + λ1)2 = 4a(y-λ2)
This should have only one real root. (or 2 repeated roots!)
am i right?
Two parabolas y2=4a (x-lambda1) and x2=4a (x-lambda2) always touch each other(lambda1,lambda2 being variable parametres). then their point of contact lies on a
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