y = x2 + 2px + p2 + 13 - p2
y - ( 13 - p2 ) = ( x + p )2
So vertex is ( - p, 13 - p2 )
What do u mean in ur Question "4 units ABOVE y-axis" ???
shouldn't it be x-axis?
if so, u should have 13 - p2 = 4
giving p = ± 3
the value of p such that the vertex of y=x2+2px+13 is 4 units abovethe y-axis,is
a}2 b}+ - 4
c. 3 d. -3
y = x2 + 2px + p2 + 13 - p2
y - ( 13 - p2 ) = ( x + p )2
So vertex is ( - p, 13 - p2 )
What do u mean in ur Question "4 units ABOVE y-axis" ???
shouldn't it be x-axis?
if so, u should have 13 - p2 = 4
giving p = ± 3