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a parabloa y^2=4x is given.also family of lines 2ax+by+2c=0 is given where a,b,c are in AP
Q1 waht is combined eqn of members of family of lines where tangents are to a give parabola
Q2 if secants are drawn to above parabola from pt of interxection to given family of lines,then locus of mid points of segments of secants intercepted b/w parabola
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UP 0 DOWN 0 0 2
2 Answers
11Pls make ur qsn clearer in 1)
2) Point of interesection is (1,-4).
Eqn of any line through this is y+4=m(x-1)
Equating this with parabola eqn y2=4x, we get y1+y22=k=2m
Similalrly we have the eqn m2x2+(m+4)2-(2m2+8m)x=4x, we can thus eleminate 'm' from these 2 equations, and get reqd locus........
Nudge if prob not cleared.