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Prove that from a point (a,b) of the circle x(x-a) + y(y-b) = 0, two chords, each bisected by the axis of x, can be drawn if a²>8b²

1 Answers

so x1,-b lies on the circle.

thus it should satisfy the equation x²+y²=xa+yb

=> x1² + b² = x1.a - b²

=> x1² - x1.a + 2b² =0

since x1 should be real...

therfore, D> 0

so, a² > 8b²

proved

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