1y this is not pinked ?? [7] [7]
prove that all pts lying inside triangle formed by pts. (1,3),(5,0),(-1,2) satisfy 3x+2y≥0 and 2x+y-13≥0
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13 Answers
11) find the equations of the three sides.
2) find the condition for which points are within the triangle.. (see whether it includes or excludes zero)
3) then compare the three lines, u will get the ans i mean the proof...
1arey mujhe abhi poora solve karni hai ??
[2] [2]
dekho......
first find the eqn of all the three sides...
then find out the conditions for which one point will be inside the triangle.
jus do it.. wid pen n paper.. [3]
u will get to know..
1see for ex for a point to be inside a circle : x^2 +y^2 < r^2
similarly try to get that condition ..
simply chcek which line consists origin, which do not ... n all...
1[aur main zaada nahi bolungi... yeh tumhara doubt thori na tha [3] ... maine isko dhund ke nikali pink karwane ke liye... tumne doubt kyun puchha [7] [4] [3]]
3eureka i think the inequality must be 2x+y-13≤0 can u check the question.
1is it??
i think its corect... but it was one month ago i did this...
so forgot .... but i think i had got ..
1chcek it...
u got y-2x-13=0 line .... but he has asked for y+2x-13=0 line..
1Problem is wrong
no point lying inside the triangle will satisfy second inequality
1second inequality must be reverse.
if second inequality is reversed then check only for vertices.
if vertices satisfy the inequality then every point inside the triangle must satisfy the inequality...
