ROLL ON ....CIRCLES

The second circle has centre (2,-3) and radius 4 so radius of first circle must be 1
and so its eqn is (x+1)²+(y-1)² = 1

Yes correct Philip

So , Intercepts made by the circle on the coord axes r 0 & 0

come on pump up the level a little bit

OK TRY this

2 ) A circle C is a tangent to the x & y axes at the points P n Q respectively ,BC & AD r parallel tgts to the circle with slope -1

If the points A & B r on the y-axis while C & D on the x-axis & area of ABCD is 900√2 sq.units

Then find the radius of the circle

hey d radius is 15 units isnt it????

let d eq of BC be x + y=c₁ n dat of AD be x+y=c₂..let d radius be r
using distance formula

c₁-c₂√2=2r

again cordinates of d centre are r,r

if we use distance formula to equate the distance 4m the 2 tangents we get

2r-c₁√2=c₂-2r√2

or c₁+c₂=4r

area =900√2units
so c₁²-c₂²=1800√2units

if we solve all these we get r=15units

Here's one more ...........

3 ) Find the eqn of circle passing thru (1,1) belonging to the coaxial system of circles that r tangent at

(2,2) to the locus of the point of intersection of mutually perpendicular tangent to the circle

x² + y² = 4