Short-cut for Ellipse

IIT JEE 2015 Papers › Co-ordinate Geometry questions › Short-cut for Ellipse

Any shortcut method to find out the length of major and minor axes of an ellipse from its standard 2nd degree equation?

#Mathematics #Co-ordinate Geometry

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redox ·2011-02-18 04:07:57

translation of axes

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kunl ·2011-02-18 04:10:55

yo!

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swordfish ·2011-02-18 17:00:14

Without completing the squares, find out the length of major and minor axes.

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sankettopper gupta ·2011-02-18 21:23:32

why do you need a shortcut in the case which itself is short.

a shortcut will be required in the case where the equation of the ellipse is like ax²+by²+2Î»xy +.. something like that where you have to rotat e the axis by tanÎ¸=2h/a-b

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sagnik sarkar ·2011-02-19 23:31:06

@swordfish

Firstly find the centre of the ellipse which here comes out to be (-5,2)
Now, put x=-5 + r cos(theta)
y=2 + r sin(theta) in the eqn of the ellipse,

then maximising r we can get length of major axis= 2 * r(max)

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Short-cut for Ellipse

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