in which ratio the line 3x+4y+2=0 divides the distance between between 3x+4y-5=0 and 3x+4y+5=0??
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2 Answers
ambrish biredar
·2011-02-06 04:16:45
distance between the lines given by
betn 3x+4y+2=0 and 3x+4y-5 is 7/√25
betn """""""'"""""and 3x+4y+5 is 3/√25
then 7:3