Str Lines

The ends of a rod of length l moves on 2 mutually perpendicular lines.Find the locus of the point on the rod which divides it in the ratio 2:1.

8 Answers

11
Gone.. ·

sum1 pls do this

3
iitimcomin ·

HINT use trigo!!!

3
iitimcomin ·

(3y/l)^2 + (3x/2l)^2 = 1 [takin point of intersection of those two[perp] lines as origin]

1357
Manish Shankar ·

take the ends of rods as (x,0) and (0,y)

required point P is find the point (h,k) on the rod which divides the length in ratio 2:1

the put h, k in x2+y2=l2

11
Gone.. ·

very nice idea manish bhaiya ... thank You ! :)

11
Gone.. ·

bhaiya ans is not matching :(

3
msp ·

i think the ans will be an ellipse.

1
Mirka ·

locus of the reqd point will be

(3x/2)2 + (3y)2 = L2

or

(3y/2)2 + (3x)2 = L2

It's an ellipse.

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