1drop a perpendicular from C on AB let the foot be D
\cot A + \cot B =\frac{1}{CD}*AB(constant)
this implies
CD =constant
which means parallel line to AB
A & B are fixed points.
The vertex C of triangle ABC moves such that cot a + cot b=constant.
The locus of C is a straight line
a> perpndicular to AB.
b> parallel to AB.
c> inclined at angle(A-B) to B.
d> none of the above.
please post the soln. along with the answr...
please help...
-
UP 0 DOWN 0 0 2
2 Answers
1