1let equation of circle be
passes through ( 2, 0) and ( 0, 2 )
passes ( 2,0)---1
passes ( 0,2 )
--2
solve des
and for orthogonality use
2gg1+ 2ff1 = c + c1
also u can consider those points as end of diameter
Find the eq. of the circle which passes through the points (2,0) and (0,2) and orthogonal to the circle 2x2+2y2+5x-6y+4=0
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UP 0 DOWN 0 0 6
6 Answers
1try it using the same method
take the stand form and substitute the points and then apply condition for orthogonal circles. you'll get 3 equations and solve them.you'll get the circle.
13How can I solve 1 and 2 when there are 3 unknown values namely g,f and c
3If I try doing it using the old method I am getting a relationship between g and f but not the values and the constant term is getting eliminated while the answer given is 7x2+7y2-8x-8y-12=0
1solvin 1 and 2
u get g=f na ???
use it in orthogonality equation