1plz solveee
11 Answers
62in the above post, we know that AP' = 4
AP=3 and CP' = 5
the reason is that angle PCP' = 60 degree and CP=CP' so CPP' is equilateral triangle.
9pls find the fallacy im getting this situation is impossible
consider P as O
A as 3a'
B as 4b'
C as 5c' where a',b',c' are unit vectors
now for any eq Δ
Z12+Z22+Z32 = Z1Z2 +Z2Z3 +Z3Z1
ie 9+16+25 = 15a'.c' +20b'.c'+12a'.b'
RHS ≤ 47 as dot products≤1
LHS ==50
rendering situation impossible ?????????????????
1what you have done is messing up with vector and complex.
See that if z \in \mathbb{C}, z\equiv Re(z)\hat{i}+Im(z)\hat{j}.
But z^2\not=Re(z)^2+Im(z)^2.since z ≠Re(z)+Im(z).
9thanks ith power i was wondering y i had made such a stupid error
916 B
17 A
solution is quite dirty ( used cartesian system with P(x,y) )
is there a three line solution or a special property that we can use
11for my consideration
if we locate the point P then we can rotate it
but no such property coming in mind which could solve this question quickly
i am in complete sink with #5
i think that way this could be soleved [1]