aX(bXc)=b/√2+c/√2
=>(a.c)b-(a.b)c=b/√2+c/√2
=>a.b=-1/√2
=>mod(a)mod(b)cosθ=-1/√2
=>θ=3π/4
if a,b,c are non coplanar unit vectors such that
a X(bXc)=b+c/√2 then the angle between a and b is:
-
UP 0 DOWN 0 0 4
4 Answers
eureka123
·2009-03-09 04:05:39