sorry, i dont know how to keep bars overhead
let angle between a and b be cos θ . u =a-b cosθ
|v|=sinθ
u^2= 1+cos2θ-2cos2θ
=1-cos2θ=sin2θ =|v|2
Let a and b be 2 non collinear unit vectors . u=a-(a.b)b and v = a x b,then |v| = ? (in terms of u , a,b)
sorry, i dont know how to keep bars overhead
let angle between a and b be cos θ . u =a-b cosθ
|v|=sinθ
u^2= 1+cos2θ-2cos2θ
=1-cos2θ=sin2θ =|v|2