33Nobody........
In the definition of conics the fixed pt doesn't lie on the directrix but what will be the geometric figures if the fixed pt lie on the directrix for different cases i.e.
1) e<1
2) e=0
c)e=1
d)e>1
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16 Answers
1e=1 .. staright line perpendicular to this line.. i again make mistake.. but dont know if this answer again is mistake :))
33for e=1 perpendicular line is correct but......... except point F
33last question:
yes correct ,it will capture all point except perpendicular and pt F for different values of e.
but for a given value of e it will give pair of lines passing through F inclined at an angle sin-1(1/e) with given line and leaving the fixed point.
1Let the point be P , focus S , and point on the fixed line M .
case 1) e<1 w.k.t PS / PM = e
PS =e PM
< PM , but PM is zero . as dist can't be -ve . NULL set.
case 2) e>1
PS > PM , true for all points in the plane. as PM =0
Is my argument correct? unable to understand nor am I getting anywhere to solving for the other two.
62no srinath.. there is a slight mistake...
If i said x>y
and i said x=ky (k>1)
(In the question k is fixed..... not that k can take any value)
does the 2nd statement imply the first? no it does not..
Just look into the 2nd one.. i guess u will get a better solution! (a more refined one!)
62See srinath the reason why you are getting confused is that e<1 is given...
Now you should only take e as a fixed e.. but less than 1...
So e will not span all values less than 1.. but it will be some constant value (which is fixed)...
What you have done is taken the union over all e's <1 .
So your answer is more or less the union of all possibilities :)