QT P1 9

VITEEE Questions › Disucss Test Questions questions › QT P1 9

The following question contains ONE OR MORE correct answer

The power dissipated in resistor is 15W. The reading of ammeter and voltmeter are 500mA and 10V respectively. Ammeter, voltmeter and battery are ideal

(A) the resistance R1 is 20 ohm

(B) the resistance R3 is 15 ohm

(D) power supplied by battery is 22.5 W

#Miscellaneous #Disucss Test Questions

UP 0 DOWN 0 1 5
Post on FacebookPost anonymously?

5 Answers

UTTARA ·2010-02-28 12:58:50

1 2 3

Options r correct

But what abt 4th??

This was my doubt

ANS GIVEN : 1 2 3 4

UP 0 DOWN 0
Post on FacebookPost anonymously?

rahul nair ·2010-02-28 21:39:51

Power supplied =V²/R

Eff resistance=(R1+R2) in parallel with R3
=10ohms
Power=22.5W

UP 0 DOWN 0
Post on FacebookPost anonymously?

UTTARA ·2010-02-28 21:43:40

V remains same in parallel

So power = 15 x 15 / 15 no??

UP 0 DOWN 0
Post on FacebookPost anonymously?

rahul nair ·2010-02-28 21:47:45

V remains same in parallel

V across R3=15
Pow.=15*15/15=15

V across R1+R2=15
Pow=15*15/30=7.5

total pow=p1+p2=22.5

UP 0 DOWN 0
Post on FacebookPost anonymously?

UTTARA ·2010-02-28 21:53:41

Ok Thanks

Agreed with the given answer

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

Close [X]

QT P1 9

5 Answers

Your Answer

Add Image

Similar Questions