we have ,
dy/y=dx/x
hence, logy=logx+logc
=> y= cx ,
or logy=logx+c
=> y/x=e^c=k(another constant)
both a and c options must be correct as the value of c will adjust acc. to the sign
hence both are equal
we have ,
dy/y=dx/x
hence, logy=logx+logc
=> y= cx ,
or logy=logx+c
=> y/x=e^c=k(another constant)