SOLUTION GIVEN :
the origin is shifted to (4,4) so let eqn. is X2/a2+Y2/b2=1
then the vertices in new coordinates are (1,0) & (-1,0) so a=2 also b=√3
BUT I THINK SO, IT SHOULD BE 2a=2 AND NOT a=2
AND HENCE a=1
find the eqn. of the ellipse whose vertices are (5,4) & (3,4) and eccentricity is 1/2
SOLUTION GIVEN :
the origin is shifted to (4,4) so let eqn. is X2/a2+Y2/b2=1
then the vertices in new coordinates are (1,0) & (-1,0) so a=2 also b=√3
BUT I THINK SO, IT SHOULD BE 2a=2 AND NOT a=2
AND HENCE a=1