Test:13 QNo:10

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a is chosen as a random natural number. what is the probability that (x-1)(x-10)(x-a) has no repeated roots?

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sridharm chandra ·2009-12-07 04:37:22

probability cannot be dtermined

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sridharm chandra ·2009-12-07 04:38:55

savandi

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cute_cat ·2010-05-27 00:37:41

can someone explain???

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Pritish Chakraborty ·2010-05-27 19:45:45

No repeated roots as in....a cannot be 1 or 10, isn't it?
There are n natural numbers. Probability that a is 1 or 10
= P(1 or 10)
= P(1) + P(10)
= 1/n + 1/n
= 2/n

So probability that a is not 1 or 10 is given by
P(Not 1 or 10)
= n - 2n

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rishicomplex ad ·2010-12-06 22:31:49

answer should be 1 their ans is rong

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Test:13 QNo:10

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