11Fdt=m{(10(2)1/2*1/21/2)+m(10)}i+m(10(2)1/2*1/21/2)j
=20mi+10mj
A football of mass m approaches at 10m/s and is kicked by the footballer such that it returns at 10√2 at an angle of 45 degrees from its initial direction!
What is the magnitude of the impulse?
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3 Answers
23Impulse I = Δp = m Δ v = m (vfinal - vinitial )
vfinal = 10 i + 10 j
vinitial = - 10 i
so I = m ( 20 i + 10 j)
| I | = √202+102