3Apply energy conservation and newtons laws.
A man scubadives from a cliff with
a rope of length 490 metres. Once the rope becomes taut, a deceleration of
98 m/s2 starts to act. Find the maximum depth from the top of the cliff
that he will reach?
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3 Answers
1
Velocity of the man as he covers the distance of the rope,
v2-u2=2as
v=√2gh
=98 ms-1
Distance travelled while decelerating with a= -98ms-2,
v2-u2=2as
0-982=2(-98)s
s=49 m
Therefore, the total height through which he falls,
H=h+s
= 490+49 = 539 m
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