Test:20 QNo:2

lim-x→0 (tanx-sinx)/x3=

4 Answers

1
sahil jain ·

ans is 16.

1
nihal raj ·

ANS IS 1/2

1
BODO ·

of corse its 1/2

11
Joydoot ghatak ·

yes the answer is 1/2.

let I = lim x→0 (tan x - sin x)/ x3.
= limx→0 ( x + 1/3 x3 +2/15 x5.......) - (x -1/6 x3 +1/120 x5) / x3
{by applying expansion.}
=limx→0 1/2 x3 + 17/120 x5......./ x3
=limx→0 1/2 + 17/120 x2......
= 1/2.

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