1
dhruvin
·2009-11-15 03:52:30
can u explain how to get it?
1
Grandmaster
·2009-11-15 05:20:15
Hey, what are the correct statements
23
qwerty
·2009-11-15 05:26:22
take a standard quadratic f(x)=ax2+bx+c
f(x)=x
ax2+bx+c=x
i.e ax2+(b-1)x+c=0
the roots of dis eqn are alpha and beta.
now find f(f(x)) by replacing x by f(x)i.e by replacing x by ax2+bx+c
i think so this is how it shud be done ..but its a very lengthy method, there is suerly another method to it ...
33
Abhishek Priyam
·2009-12-26 11:11:31
Its discussion is here:
http://targetiit.com/iit-jee-forum/posts/biquadratic-2135.html
and grandmaster correct statements are?:
a) If α β are real and distinct then γ and δ are not real.
b) If α+β=γ+δ then none of α β γ δ are real.
c) If α=β(real) then γ and δ are real.
d) None
ans :b