Test:227 QNo:3

VITEEE 2015 Guidance › Disucss Test Questions questions › Test:227 QNo:3

In Î”ABC the median AD is perpendicular to AC. If b=5 and c=11 then a is equal to

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anmol111 ·2011-03-14 06:16:32

it would be helpful if the reply is sent fastly.... Answer given is 14

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ninepointcircle ·2011-03-14 07:29:39

See it is very using Stewarts theorem
http://en.wikipedia.org/wiki/Stewart's_theorem

By stewarts theorem we get
b²a2 + c²a2 = a( AD²+ a2 . a2 )
Putting values and solving
73 = AD² + a²4
Adding 25 (i.e b²) to both sides we get
98= AD² +b² + a²4
98 = a²4 + a²4
a² = 196
a = 14 units
:)

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Basic Integral Calculus Operators Symbols Matrix Cases

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+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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Test:227 QNo:3

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