Test:244 QNo:3

One mole of monoatomic ideal gas is mixed with one mole of a diatomic ideal gas. The molar specific heat of the mixture at constant volume is

2 Answers

C_{V(mix)}= \frac{1*\frac{3R}{2}+ 1*\frac{5R}{2}}{2} = 2R

but the answer given is 4R

C_v=(1*3R2+1*5R2)1+1 =2R

But the answer is 4R.

Plz explain.What is the correct answer?????

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