s>sp>sp2>sp3>p
BCOZ percentage s character directly to enegy
@ Aashish
p orbital has higher energy than s then how your answer can be correct?
@aashish
s orbital nucleus ke paas hota hai thats why woh stable hai aur stability ki condition ke anusar energy sabse kam honi chahiye.
henceforth myconclusions are:
sp3- s:25%
sp2- s:33%
sp- s:50%
s -100%(yeh mat puchna kyo)
order is (in increasing order)
s<sp<sp2<sp3<p
its very confusing yaar, give the congent reason.
why the energy decreases as we move away from nucleus, don't you guy thinks it should increase, for example take our planetary system as we move away from the sun the temperature decreases, then why here its opposite,i.e, as we move away from nucleus the energy is increasing. Or see the concept of electronegativity, as we move away from nucleus the electronegativity decreases, doesn't this imply that the energy of the orbit and so of orbitals is decreasing (I think I would get answer for this ki as electrons are increasing in the orbits, so the electronegativity decreases)
And alkanes are sp3 hybridized, but they are least reactive whereas alkenes which are sp2 hybridized and alkynes which are sp hybridized are more reactive, Doesn't this imply ki sp3 hybridization are at lower energy level, hence more stable.
I studied about the relative bond strength of these orbitals according to which
s = 1
p = 1.73
sp = 1.93
sp2 = 1.99
sp3 = 2
If we go by this, then it implies that we'll have to provide more energy to the sp3 and the energy order would be
sp3>sp2>sp>p>s
I know quite confusing, but kya karen majboori ka naam JEE
hey khyati energy increases as we move away from nucleus becoz near the nucleus stability increases due to attractive forces and for stabillity energy is to be given out but as we move away from nucleus electrons are of higher energy due to decreased nuclear charge..idea can be taken from ionisation enthalpy.........
yes, and an electron more away frm the nucleus can be more easily removed frm that atom.
now s orbital is closest to nucleus , so u require very high energy for removing electron frm s orbital , so u can even say that electron is s orbital has least energy than that in other orbitals.
now energy of an orbital actually means energy of an electron in dat orbital , so s will be having least energy.
so more the s character of an orbital , less is its energy, hence the order