10 identical cells, each of emf 12V and internal resistance 0.1Ω, are joined in series. Out of these , 3 cells are wrongly connected, i.e., their terminals are connected in reverse of that required for series connection. Let ε0 be the emf of the resulting battery and r0 be its internal resitance,
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3 Answers
virang1 Jhaveri
·2009-04-15 23:02:12
3 wrong 6 right
But 3 wrong will nuetrelize 3 rite
Therefore only 3battery will be providing e0
ε0 = 36V
The internal resistance will add therefore r0 = 1Ω