Test:33 QNo:6

JEE Advanced 2015 Questions › Disucss Test Questions questions › Test:33 QNo:6

lim(x→0) 1/x²-1/(xsinx)

#Miscellaneous #Disucss Test Questions

UP 0 DOWN 0 0 3
Post on FacebookPost anonymously?

3 Answers

1

shankyshanky shanky ·2010-02-16 16:42:59

explaination of q-06

UP 0 DOWN 0
Post on FacebookPost anonymously?

13

Avik ·2010-02-16 21:38:29

\frac{1}{x^2}-\frac{1}{x.Sin(x)} = \frac{Sin(x)-x}{x^2.Sin(x)}\\ \\ Use \ taylor \ series \ expansion\ , \frac{\left( x-\frac{x^3}{6}+...\right)-x}{x^2.\left(x-\frac{x^3}{6}+...\right)} \\ \\ \\ Which \ reduces \ to , \ \lim_{x \rightarrow 0} \frac{\left(\frac{-1}{6}+ x(...)\right)}{1- x(...)} = -1/6

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

Anirudh Kumar ·2010-02-17 07:59:37

one other way is to apply L'hospital rule.

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω