ans k=5?
let x,y,z be the common point
we have x=3+λ
y=2λ+1
z=3λ+2
so we have
(3+λ-k)/1=(2λ+1-5)/2=(3λ+2-2)/1
we get 2λ-4=6λ thus λ=-1
so we get
2-k=-6/2
k=5
If the lines (x-3)/1=(y-1)/2=(z-2)/3 and (x-k)/1=(y-5)/2=(z-2)/1 intersect then k is
ans k=5?
let x,y,z be the common point
we have x=3+λ
y=2λ+1
z=3λ+2
so we have
(3+λ-k)/1=(2λ+1-5)/2=(3λ+2-2)/1
we get 2λ-4=6λ thus λ=-1
so we get
2-k=-6/2
k=5