4 Answers
sumit_kumar
·2010-02-05 08:31:20
Q10 find dy/dx at x=e, y=e2x/logx
a) (e-1)e2e/e
b) o
c) 1
d) (e2-1)e2e/e
Correct Answer: (a)
Maths Musing
·2010-02-05 09:18:22
Given y log x = e2x
so y . [ d/dx { log x } ] + log x . [ d/dx { y } ] = d/dx { e2x }
or , y / x + dy /dx { log x} = 2 e2x
or , after simplification , dy / dx = 2 e2x - { y / x }log x
So dy / dx at x = e ,
is 2 e2e - e2e - 11 or , ( 2e - 1 ) e2ee
I really think the answer's wrong :( :( :(