solve this question plz
2 Answers
Anirudh Narayanan
·2009-04-28 01:48:55
take log on both sides,
log y = C√x (where c = log√e)
y'/y = C/2√x
thus, y' = C√e√x/2√x
take log on both sides,
log y = C√x (where c = log√e)
y'/y = C/2√x
thus, y' = C√e√x/2√x