1/(1.3)+1/(3.5)+1/(5.7)+....... to n terms is
1dude the series which u have given can be written as
1/2[(3-1)/(3.1)+(5-3)/(5.3)+.......................................+((n+2)-n)/(n+2).n] which is equal to
1/2[1-1/3+1/3-1/5+....................................................+1/n-1/(n+2)] in which u will fin that except the first and the last term all get canceled and hence u get 1/2[1-1/(n+2)]=1/2[(n+1)/(n+2)] and hence non of the ans matches with tell me if i am wrong.
1@santoshprasad
i think ur general term is wrong....
nth term should be......((2n+1)-(2n-1))/((2n+1).(2n-1)).........
after cancelling the terms what remains is........1/2 [1-1/(2n+1)]....
after simplification......n/(2n+1).......tell me if i m correct.....